Consider the planes 3x-6y+22+5=0 and 4x-12y+32=3.Theplane 67x-162y+47z+44=0 bisects the angle between the given planes which

3x-6y+22+5=0-------- (i) 

-4x+12y-32+3=0 --------(ii)

Bisector  $\frac{3\mathrm{x}-6\mathrm{y}+2\mathrm{z}+5}{\sqrt{9+36+4}}=\pm \frac{-4\mathrm{x}+12\mathrm{y}-3\mathrm{z}+3}{\sqrt{16+144+9}}$

The plane which bisects the angle between the planes that contains the origin. 

13(3x -6y+22 + 5) =7 (4x+ 12y-3z + 3) 

67x - 162y + 47z + 44=0 ----------(iii)

Further, 3 x (-4) + (-6) (12) + 2 x (-3) < 0 

Hence, the origin lies in the acute angle.