Q.

Consider the planes P1,P2 and points A(2, 5, 1) and B(1, 3, 0) where
 P1:x+y+z=3P2:2x+yz=4
Then which is/are CORRECT ?

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a

Projection of segment AB on P1 is equal to 22 units 

b

Area enclosed by locus of all points on P1 which are at a distance of 3 units from B is equal to 26π3sq. units.

c

Projection of segment AB on P1 is equal to 63units

d

Shortest distance between line AB and points common to P1,P2 is equal to 153units.

answer is A, B, D.

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Detailed Solution

detailed_solution_thumbnail

 (A) n¯1×n¯2=2,3,1
Point common to P1 and P2 is (1, 2, 0)
 distance between skew lines is
(a¯c¯)(p¯×q¯)|p¯×q¯|=153
Question Image
BA=i^+2j^+k^
Angle between line and plane
=sin1436=θ
Projection is |BA|cosθ=6×218=63
 (D) r=263
Area =r=26π3Question Image

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