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Q.

Consider the points A=(0,1)&B=(2,0),P be a point on the line 4x+3y+9=0 Co-ordinates of the point ‘P’ such that |PAPB| is maximum is

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a

(65,175)

b

(245,175)

c

(845,135)

d

(125,175)

answer is D.

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Detailed Solution

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|AB||PAPB|

So PAPB is maximum when P is collinear with AB.
Equation of  ABy1=12(x0)
 x+2y=2(i)
& solve with  4x+3y+9=0(ii)
(i) & (ii)
P=(245,175)

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