Consider the process $N_2\to N_2^{+}+e^{-}$ 

Choose correct statements for above process

for these process $N_2\to N_2^{+}+e^{-}$ all the given option is correct because The electron from a -orbital is lost during the process of forming N2+ from N2.

M.O configuration of N2​ is:

$\sigma 1{\mathrm{s}}^2{\sigma }^{\ast }1{\mathrm{s}}^2,\sigma 2{\mathrm{s}}^2{\sigma }^{\ast }2{\mathrm{s}}^2,\pi 2{\mathrm{p}}_{\mathrm{y}}^2\pi 2{\mathrm{p}}_{\mathrm{z}}^2,\sigma 2{\mathrm{p}}^2$

M.O configuration of N  2 +  is:

$\sigma 1{\mathrm{s}}^2{\sigma }^{\ast }1{\mathrm{s}}^2,\sigma 2{\mathrm{s}}^2{\sigma }^{\ast }2{\mathrm{s}}^2,\pi 2{\mathrm{p}}_{\mathrm{y}}^2,\pi 2{\mathrm{p}}_{\mathrm{z}}^2,\sigma 2{\mathrm{p}}_{\mathrm{x}}^1$

Thus, the - orbital loses two electrons.

In this process, bond order decreases and this Process is endothermic