Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Consider the quadratic polynomial  f(x)=x2px+q  where  f(x)=0 has prime roots If  p+q=11  &  a=p2+q2 then  f(a)=λ (a is an odd positive integer) Number of even  positive divisors of   is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

8

b

12

c

6

d

4

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

[α+β=p,αβ=2  and p+q=11 α+β+αβ=11 α=11β1+β β=2, α=3 p=5,  q=6 a=61 f(61)=(61)26.61+6=3422   3422=2×29×59    

Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon