Consider the reaction, 12H+12H→23He+01n,m(12H)=2.014082u,m(23He)=3.016029u m(10n)=1,008665u . Then, mark the correct option

Δm= mass defect =2 m(12H)−m(23He)−m(01n)⇒ Q-value =[mass( reactants) - mass (products) ]×931.5=3.232MeVAs Q-value is positiveSo, no threshold energy is required

Consider the reaction, 12H+12H→23He+01n,m(12H)=2.014082u,m(23He)=3.016029u m(10n)=1,008665u . Then, mark the correct option

Δm= mass defect =2 m(12H)−m(23He)−m(01n)⇒ Q-value =[mass( reactants) - mass (products) ]×931.5=3.232MeVAs Q-value is positiveSo, no threshold energy is required

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Consider the reaction, $_{1}^{2} H +_{1}^{2} H \to_{2}^{3} H e +_{0}^{1} n, m (_{1}^{2} H) = 2.014082 u, m (_{2}^{3} H e) = 3.016029 u$ $m (\begin{array}{l} 1 \\ 0 \end{array} n) = 1, 008665 u$ . Then, mark the correct option

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Threshold energy of 3.23 MeV is required to initiate the reaction

An amount of energy 3.23 MeV will be released in this reaction

Reaction occurs such that final total KE is 3.23 MeV lesser than total initial KE

No, threshold energy is required for the reaction

answer is B, D.

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Detailed Solution

$Δ m = mass defect = 2 m (_{1}^{2} H) - m (_{2}^{3} He) - m (_{0}^{1} n)$
$\Rightarrow Q-value = [mass (reactants)$ - $mass (products)] \times 931.5 = 3.232 MeV$
As Q-value is positive
So, no threshold energy is required