Q.

Consider the reaction at 300K

H2(g)+Cl2(g)2HCl(g); ΔH=185kJ

If 2 mole of H2 completely react with 2 mole of CI2 to form HCL What is ΔU for this reaction?

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a

370 kJ

b

-370 kJ

c

0

d

-185 kJ

answer is D.

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Detailed Solution

H3+Cl22HCL,ΔH=18kJ1mol         1mol 2mol3mol          3mol 6molΔng=0ΔH=ΔU6ΔU6=ΔH=185KJ

For2molesofthereaction, ΔU=185×2=370kJ

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