Q.

Consider the sequence of numbers a0,a1,a2,....,an where  a0=17.23, a1=33.23 and  ar+2=12(ar+ar+1) then 

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a

|a8a7|=18

b

a0a1,a1a2,a2a3,...... are in GP

c

|a10a9|=|a8a7|

d

 a0a2,2(a1a2),a1a3,...... are in HP

answer is A, B, C.

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Detailed Solution

Let,  ar+2=12(ar+ar+1)

2ar+2=ar+ar+1 2(ar+2ar+1)=arar+1 ar+2ar+1=12(ar+1ar) Put,  r=8,7,6,5,4....,3,2,1,0 a10a9=12(a9a8) =(12)(12)(a8a7) =(12)(12)(12)(a7a6)

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=129(α1α0)=(129)(16)=125=132

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Consider the sequence of numbers a0,a1,a2,....,an where  a0=17.23, a1=33.23 and  ar+2=12(ar+ar+1) then