Consider the situation of the previous problem. Let the water push the left wall by a force F₁ and the right wall by a force F₂.

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$F_{1} = F_{2}$

$F_{1} > F_{2}$

$F_{1} < F_{2}$

answer is B.

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Detailed Solution

The water inside the box receives a pseudo force (ma) towards left when the box accelerates towards the right, where m is the mass of the water.
As a result, the water's F1 force is stronger against the box's left wall.
In an accelerating liquid, the pressure due to acceleration relies on the horizontal distance from the leading surface, just as it does in a liquid at rest.

Hence the correct answer is $F_{1} > F_{2}$ .

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