Consider the situation of the previous problem. Let the water push the left wall by a force F₁ and the right wall by a force F₂.

• The water inside the box receives a pseudo force (ma) towards left when the box accelerates towards the right, where m is the mass of the water. 
• As a result, the water's F1 force is stronger against the box's left wall.
• In an accelerating liquid, the pressure due to acceleration relies on the horizontal distance from the leading surface, just as it does in a liquid at rest.

Hence the correct answer is ${\mathrm{F}}_1>{\mathrm{F}}_2$.