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Consider the situation shown in figure. Water $(μ_{w} = 4 / 3)$ is filled in a beaker upto a height of 10 cm. A plane mirror is fixed at a height of 5 cm from the surface of water. Distance of image from the mirror after reflection from it of an object O at the bottom of the beaker is:

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12.5 cm

15 cm

7.5

10 cm

answer is B.

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Detailed Solution

apparent depth $d' = \frac{Real depth}{μ} = \frac{10}{4 / 3} = 7 .5 cm$

$∴$ Objective distance, $u = 5 + 7.5 = 12.5 cm$

$∴$ Image distance, $v = 12.5 cm$

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