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Consider the spectral line resulting from the transition from n = 2 to n = 1 in the atoms and ions given below. The shortest wavelength is produced by

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$L i^{+ +}$

deuterium atom

$H e^{+}$

hydrogen atom

answer is D.

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Detailed Solution

Since $λ$ (wavelength of radiation) $α \frac{1}{z^{2}}, L i^{+ +}$ will emit the shortest wavelength as its atomic number is highest among the elements given.

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