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Q.

Consider the structure of $A l_{2} {(C H_{3})}_{6}$ compound and find the value of $A + B + C$
A = Maximum number of atoms in one plane
B = Total number of $2 c - 2 e^{-}$ bonds
C = Total number of $s p^{3}$ hybridized atoms

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answer is 40.

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Detailed Solution

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$A + B + C 10 + 22 + 8 = 40$

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