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Q.

Consider the structure of $A l_{2} M e_{6}$ compound and find the value of $\frac{x + z}{3}$
Where $x =$ no of $2 c - 2 e^{-}$ bonds
$z =$ total no of $3 c - 2 e^{-}$ bonds

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answer is 8.

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Detailed Solution

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x=22, z=2

$\frac{x + z}{3} = \frac{24}{3} = 8$

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Consider the structure of Al2Me6 compound and find the value of x+z3Where x= no of 2c−2e− bonds z= total no of 3c−2e− bonds