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Consider three elements with the following abbreviated electronic configurations
$X = [A r] 4 s^{2}; Y = [N e] 3 s^{2} 3 p^{4}; Z = [A r] 3 d^{10} 4 s^{2} 4 p^{4}$
Then which of the following statements is/are correct:

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X is metal; Y is non metal

The element having highest atomic size is X

The element having highest Ionization energy is Z

The element having highest electron affinity is Y

answer is A, B, D.

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X is metal; y and z are non metals

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