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Q.

Consider three matrices A=2141 , B=3423 and C=3423  thentr(A)+tr(ABC2)+tr(A(BC)24)+tr(A(BC)38)+......=

 

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a

6

b

9

c

12

d

0

answer is A.

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Detailed Solution

BC=34233423=1001=I 

tr(A)+tr(ABC2)+..=tr(A)+tr(A2)+...

=tr(A)112=6

 

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Consider three matrices A=2141 , B=3423 and C=3−4−23  thentr(A)+tr(ABC2)+tr(A(BC)24)+tr (A(BC)38)+......=