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Consider three non- collinear points A, B, C with co-ordinates (0,6), (5,5) and (-1,1) respectively. Equation of a tangent line through the origin with respect to the circle, circumscribing the triangle ABC is ‘ax + by=0’ then The value of $\frac{a + 2 b}{a} =$

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Detailed Solution

A (0,6) B (5,5) C (-1,1) is isocels right angled at A
Question Image circle is also origin is located on this circle
Slope of tgt at origin $= - \frac{1}{slope OP}$ (Where P is centre of circle) so Tgt is 2x+3y=0

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