Consider two arbitrary decay equations and mark the correct alternative given below.i) 92230U→n+92229U ii) 92230U→p+91229PaGiven M(92230U)=230.033927 u, M(92229U)=229.033496 u, M(91229Pa)=229.032096 umn=1.008665 u,mp=1.007825, 1 amu=931.5 MeV.

For decay (i) Q=[230.033927−229.033496−1.00865]×931.5=−7.7 MeVFor decay (ii) Q=[230.033927−229.032089−1.007825]×931.5=−5.6 MeV∴ Q is negative for both the decay, so none of the decays are allowed.

Consider two arbitrary decay equations and mark the correct alternative given below.i) 92230U→n+92229U ii) 92230U→p+91229PaGiven M(92230U)=230.033927 u, M(92229U)=229.033496 u, M(91229Pa)=229.032096 umn=1.008665 u,mp=1.007825, 1 amu=931.5 MeV.

For decay (i) Q=[230.033927−229.033496−1.00865]×931.5=−7.7 MeVFor decay (ii) Q=[230.033927−229.032089−1.007825]×931.5=−5.6 MeV∴ Q is negative for both the decay, so none of the decays are allowed.

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Consider two arbitrary decay equations and mark the correct alternative given below.
i) $_{92}^{230} U \to n +_{92}^{229} U$ ii) $_{92}^{230} U \to p +_{91}^{229} P a$
Given $M (_{92}^{230} U) = 230.033927 u, M (_{92}^{229} U) = 229.033496 u, M (_{91}^{229} P_{a}) = 229.032096 u$
$m_{n} = 1.008665 u, m_{p} = 1.007825, 1 a m u = 931.5 M e V .$

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Only decay (i) is possible

Only decay (ii) is possible

Both the decays are possible

Neither of the two decays is possible

answer is D.

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Detailed Solution

For decay (i) $Q = [230.033927 - 229.033496 - 1.00865] \times 931.5 = - 7.7 M e V$
For decay (ii) $Q = [230.033927 - 229.032089 - 1.007825] \times 931.5 = - 5.6 M e V$
$∴ Q$ is negative for both the decay, so none of the decays are allowed.