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Q.

Consider two ideal diatomic gases A and B at some temperature T. Molecules of the gas A are rigid, and have a mass m. Molecules of the gas B have an additional vibrational mode, and have a mass m4 . The ratio of the specific heats (CVA and CVB) of gas A and B, respectively is 
 

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a

5:9

b

7:9

c

5:7

d

3:5

answer is B.

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Detailed Solution

Degree of freedom of a diatomic molecule if vibration is absent =5

Degree of freedom of a diatomic molecule if vibration is present=7

CvA=fA2R=52R  

and CvB=fB2R=72R
  CvACvB=57
 

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