Q.

Consider two planes P1:2x3y+z=5  and  .P2:x4y14z=5.  If a line L which is perpendicular to line of intersection of planes P1andP2  whose  one point A7,​ y1,z1 lies on the plane P1  and point Bx2,​ y2,z2  and Cx3,​ y3,z3  lie on plane P2 has the equation x+7a=yy1b=zz1c , where a,​ b,cN , then:

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

z3z2y3y2=3

b

x3x2z3z2=2

c

Least value of  a+b+c is 5

d

y1+z1​ isequalto4

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Question Image

Planes  P1​ andP2 are perpendicular L:x+7a=yy1b=zz1c

The above line lies in plane P2  and perpendicular to plane  P1A7,y1, ​z1 
 lies on both the planes
143y1+z1=5    ......i
74y114z1=5..........ii
Solving equation (i) and (ii) 
We get    y1=3andz1=0L:x+72=y+33=z01

Now, verify the options. 
 

Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon