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Q.

Considering H2O as a weak field ligand, the number of unpaired electrons in [Mn(H2O)6]2+ will be (Atomic no of Mn=25) 

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a

2

b

3

c

4

d

5

answer is D.

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Detailed Solution

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  • In [Mn(H2​O)6​)2+, Mn is present as Mn2+ or Mn (II), so its electronic configuration =1s2,2s22p6,3s23p6,3d5
  • In [Mn(H2​O)6​)2+ the coordination number of Mn is six, but in presence of weak field, ligand there will be no pairing of electrons in 3d.
  • So, it will form high spin complex due to presence of five unpaired electrons. 

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