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Q.

Considering H2O as a weak-field ligand, the number of unpaired electrons in [Mn(H2O)6]2+ will be:

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a

four

b

five

c

three

d

two

answer is C.

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Detailed Solution

The oxidation number of manganese of [Mn(H2O)6]2+ is +2. Mn2+ has the electronic configuration [Ar]3d5. 

Water is not a strong ligand, thereby no pairing of valence electrons of Mn takes place and hence, the number of unpaired electrons in Mn are five.

Hence, the correct option is option (C) two.

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