Convert ${\left(10110.0101\right)}_2$  to octal.

Thus

${\left(10110.0101\right)}_2={\left(46.24\right)}_8$

Note that, after binary point, the groups of 3 bits are made staring from left to right. That’s why we added two zeros to make a group of three bits as the, last group had only 1.