Convert the following into basic units.
(i) 28.7 pm
(ii) 15.15 ms
(iii) 25365 mg
The correct answer is

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$28 .7 \times 10^{- 11}, 1 .515 \times 10^{- 6}, 2 .5365 \times 10^{- 3}$

$2.87 \times 10^{- 11}, 1.515 \times 10^{- 5}, 2.5365 \times 10^{- 2}$

$2.87 \times 10^{- 10}, 1.515 \times 10^{- 5}, 2.5365 \times 10^{- 3}$

$2.87 \times 10^{- 10}, 1.515 \times 10^{- 6}, 2.5365 \times 10^{- 2}$

answer is B.

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Detailed Solution

$(a) 28 .7 pm \times \frac{10^{- 12} m}{1 pm} = 2 .87 \times 10^{- 11} m$

$(b) 15.15 ms \times \frac{10^{- 6} s}{1 ms} = 1.515 \times 10^{- 5} s$

$(c) 25365 mg \times \frac{1 g}{1000 mg} \times \frac{1 kg}{1000 g} = 2.5365 \times 10^{- 2} kg$

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