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Coolent used in car radiator is aqueous solution of ethylene glycol. In order to prevent the solution from freezing at $- 0 {.3}^{\circ} C$ How much ethylene glycol must be added to 5 kg of water ? $(K_{f} = 1 .86 Kkg {mol}^{- 1})$

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50 kg

50 g

45 g

40 g

answer is B.

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Detailed Solution

${ΔT}_{f} = {0.3}^{\circ} C {ΔT}_{f} = {0.3}^{\circ} C = \frac{K_{f} \times W_{B} \times 1000}{M_{B} \times W_{A}} 0.3 = \frac{1.86 \times W_{B} \times 1000}{62 \times 5000} ∴ W_{B} = 50 g The amount used should be more than 50 g$

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