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Coordination number of Cr is six. A complex with $C_{2} O_{4}^{2 -}$ , en and superoxide $(O_{2}^{-})$ will be in the ratio to make complex ${[Cr {(C_{2} O_{4})}_{x} {(en)}_{y} {(O_{2})}_{z}]}^{-}$

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answer is B.

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Oxalate and en are bidentate.

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