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Copper has a face centered cubic structure with a unit cell edge length of $3.61 A^{0}$ . What is the radius of largest atom which could be fit into the interstices of copper lattice without distorting it. The atomic radius of $C u$ is $1.28 A^{0}$

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answer is 0.52.

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Detailed Solution

$2 \times$ radius of Cu atom
$+ 2$ radius of smallest = edge length circle
$2 \times 1.28 + 2$ radius $= 3.61 A^{0}$ of smallest circle
$= 3.61 - 2.56$
$= 1.05 A^{0}$
Radius of smallest circle $= 0.525 A^{0}$

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