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Q.

Copper metal reacts with concentrated HNO3 as Cu + 4HNO3 →Cu(NO3)2 + 2NO2 + 2H2O . The number of moles of the HNO3 reduced by one mole of the Cu will be

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a

2

b

0.25

c

4

d

0.5

answer is B.

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Detailed Solution

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Cu0+HN+5O3→Cu+2(NO3)2 +N+4O2 + H2O 

Change in ox. state of 'Cu'=2

Change in ox. state of 'N' =1

Hence, 2moles of HNO3 reduced by one mole of the Cu

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