Correct combination regarding these reactions is

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I - Gatterman ; II - Gatterman

I - Gatterman ; II - Sandmeyer

I - Sandmeyer; II - Gatterman

I - Sandmeyer; II - Sandmeyer

answer is C.

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Detailed Solution

$Benzene diazoniumchloride \to_{HBr}^{{Cu}_{2} {Br}_{2}} C_{6} H_{5} Br$

$Benzene diazoniumchloride \to_{KCN}^{{Cu}_{2} {(CN)}_{2}} C_{6} H_{5} CN$

Sandmeyer’s reaction – Nucleophilic (or) free radical substitution

$Benzene diazoniumchloride \overset{Cu / HCl}{\to} C_{6} H_{5} Cl$

$Benzene diazoniumchloride \overset{Cu / HBr}{\to} C_{6} H_{5} Br$

$Benzene diazoniumchloride \overset{Cu / KCN}{\to} C_{6} H_{5} Cl$

Gatterman’s reaction – Nucleophilic substitution

Sandmeyer’s reaction gives better yield.

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