Correct match to replace -Cl group with -OH group in the following 

I)		A)	$\mathrm{NaOH},368\mathrm{K}/{\mathrm{H}}^{+}$
II)		B)	$\mathrm{NaOH}, 443/{\mathrm{H}}^{+}$
III)		C)	$\mathrm{NaOH}, 623\mathrm{K}, 320 \mathrm{atm}/{\mathrm{H}}^{+}$
IV)		D)	Warm ${\mathrm{H}}_2\mathrm{O}$

Intermediate is carbanion negative charge delocalizes at ortho & para position. 

$\therefore$ carbanion is stabilized by EWG $\left(-{\mathrm{NO}}_2,-\mathrm{CHO}....\mathrm{etc}\right)$

Carbanion is destablized by EDG $\left(-{\mathrm{OCH}}_3,-{\mathrm{CH}}_3\right)$

Greater the number of $-{\mathrm{NO}}_2$ groups at ortho & para position more will be the rate of reactivity towards nucleophilic substitution

$-{\mathrm{NO}}_2$ group at meta position has negligible effect. In fact reactivity of nucleophilic substitution