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Correct option regarding the following chemical reaction : (State T for True and F for False). $\begin{array}{l} Cd {({NO}_{3})}_{2} + {KCN}_{(excess)} ⟶ Complex X \\ \overset{H_{2} S}{⟶} ppt. ' Y^{'} \end{array}$
(P) Complex X is ${sp}^{3}$ hybridised
(Q) ppt. Y is yellow in colour
(R) Complex X is an example of imperfect complex
(S) Complex X is a diamagnetic complex

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FFTT

answer is A.

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Detailed Solution

$Cd {({NO}_{3})}_{2} + {KCN}_{(excess)} \to K_{2} [Cd ({CN}_{4}\} \overset{H_{2} S}{\to} ppt.CdS$

$K_{2} [Cd ({CN}_{4}\}$ which is an imperfect complex is sp³hybridized, cadmium sulphide is yellow in color. Since $K_{2} [Cd ({CN}_{4}\}$ has no unpaired electron it is diamagnetic in nature.

Hence, option A is correct.

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