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Correct relationship between pairing energy (P) and C.F.S.E. ( $Δ_{o}$ ) in complex ion; ${[Ir {(H_{2} O)}_{6}]}^{3 +}$ is :

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$Δ_{o} = P$

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$Δ_{o} < P$

$Δ_{o} > P$

answer is B.

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${[Ir {(H_{2} O)}_{6}]}^{3 +} : Δ_{0} > P$

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