Correct statement for dipole moment is

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$C H C l_{3} > C c l_{4} > C H c l_{2} > C H_{3} C l$

${Ccl}_{4} > {CHCl}_{3} > {CH}_{2} {Cl}_{2} > {CH}_{3} {Ccl}_{4}$

${CH}_{3} cl > {CH}_{2} {Cl}_{2} ≃ {CHCl}_{3} > {ccl}_{4}$

${CHCl}_{3} > {CH}_{2} {Cl}_{2} > {CHCl}_{3} > {CCl}_{4}$

answer is C.

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Detailed Solution

The dipole moment of CCl₄ is zero.
The dipole moment of CH₃Cl is maximum.
The correct order of the dipole moment is ${CHCl}_{3} > {CH}_{2} {Cl}_{2} > {CHCl}_{3} > {CCl}_{4}$ =CH₄

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