Correct statement(s) regarding the carbon, carbon bond lengths in the following two compounds is/are

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$C_{2} - C_{3}$ bond in the compound I is longer than the $C_{2} - C_{3}$ bond in compound-II

In Compound ‘I’ correct bond length order is

$C_{2} - C_{3} = C_{3} - C_{4} > C_{3} - C_{6} > C_{1} - C_{2} = C_{4} - C_{5}$

In Compound ‘II’ correct bond length order is $C_{1} - C_{2} = C_{3} - C_{4} > C_{2} - C_{3}$

In compound ‘II’ correct bond length order is $C_{2} - C_{3} > C_{1} - C_{2} = C_{3} - C_{4}$

answer is A, B, C.

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Detailed Solution

1,3-Butadiene $C H_{2} = C H - C H = C H_{2}$ 3R.S possible
Question Image

C-C B.L order: Question Image
3-Methylene-1,4-pentadiene 5 R.S possible

C,C-B.L order: $\underset{1.363}{C_{2} - C_{3} = C_{3} - C_{4}} > \underset{1.859}{C_{3} - C_{6}} > \underset{1.930}{C_{1} - C_{2} = C_{4} - C_{5}}$
Comparing with 1,3-Butadiene, we see that $C_{1} - C_{2}$ bond has more and $C_{3} - C_{6}$ bond has less double bond character than the double bond in the 1,3-butadiene. Resonance structures support this conclusion. $C_{1} - C_{2}$ bond has double bond character in 3 R.S out of 5 R.S while $C_{3} - C_{6}$ bond has double bond character in one R.S out of 5 R.S
B.L: $C_{2} - C_{3}$ bond in Question Image > $C_{2} - C_{3}$ bond in
In , $C_{2} - C_{3}$ bond has double bond character in 2 R.S out of 5 R.S, in $C_{2} - C_{3}$ bond has double bond character in 2 R.S out of 3 R.S