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Correct trend regarding density of alkalimetals is

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Li < Na < K < Rb < Cs

Li < Na < Rb < K < Cs

Li < K < Na < Rb < Cs

Li < K < Na < Cs < Rb

answer is C.

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Detailed Solution

Density down the group increases
Expected trend: Li < Na < K < Rb < Cs;

Due to larger interatomic distances and availability of vacant d-orbitals in potassium, density of potassium is less than that of sodium;

Actual trend; Li < K < Na < Rb < Cs

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