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Q.

cos-1a-xa-b=sin-1x-ba-bis possible if

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a

a>x>b or a<x<b

b

a>b and x takes any value

c

a<b and x takes any value

d

a=x=b

answer is A.

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Detailed Solution

a-xa-b>0, x-ba-b>0 a-b>0a>b       a-x>0      x-b>0                                     a>x>b a-b<0a<b       a-x<0     x-b<0                                     a<x<b

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