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Q.

cosxsinx8sin2xdx=

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a

sin1sinx+cosx2+c

b

sin1sinx+cosx3+c

c

sin1sinx+cosx4+c

d

sin1(sinx+cosx)+c

answer is B.

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Detailed Solution

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Put cosx+sinx=t in the integral

(cosxsinx)dx=dt

(cosx+sinx)2=t2

cos2x+sin2x+2sinxcosx=t2

 1+sin2x=t2

(cosxsinx)dx9(1+sin2x)=dt9t2sin-1t3+c

sin-1sinx+cosx3+c

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