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Q.

cos2θ-450+cos2θ+150-cos2θ-150 =

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a

12

b

13

c

12

d

13

answer is A.

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Detailed Solution

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  cos2θ-450+cos2θ+150-cos2θ-150  cos2(450-θ)+sin(θ+150+θ-150)sin(θ-150-θ-150) =1+cos2(450-θ)2+sin2θ sin(-300) =12+12cos(900-2θ)-12sin2θ =12+12sin2θ-12sin2θ =12

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