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Q.

cos24°+cos55°+cos125°+cos204°=

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a

2

b

1

c

-1

d

0

answer is B.

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Detailed Solution

cos(204°)=cos(180°+24°)=-cos24°,   cos(125°)=cos(180°55°)=-cos55° cos24°+cos55°+cos125°+cos204°=0

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