cos250cos350–sin100sin200

12[2cos250cos350−2sin100sin200] =12[cos600+cos100+cos300−cos100] =12(12+32)=3+14

cos250cos350–sin100sin200

12[2cos250cos350−2sin100sin200] =12[cos600+cos100+cos300−cos100] =12(12+32)=3+14

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cos25⁰cos35⁰–sin10⁰sin20⁰

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_{$\frac{\sqrt{3} + 1}{4}$}

_{$\frac{\sqrt{3} - 1}{2}$}

_{$\frac{\sqrt{3} - 1}{4}$}

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$\frac{1}{2} [2 \cos 25^{0} \cos 35^{0} - 2 \sin 10^{0} \sin 20^{0}]$

$= \frac{1}{2} [\cos 60^{0} + \cos 10^{0} + \cos 30^{0} - \cos 10^{0}]$

$= \frac{1}{2} (\frac{1}{2} + \frac{\sqrt{3}}{2}) = \frac{\sqrt{3} + 1}{4}$

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cos250cos350–sin100sin200

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cos25⁰cos35⁰–sin10⁰sin20⁰