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Q.

cos3θ-cos3θcosθ+sin3θ+sin3θsinθ=

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a

6

b

9

c

3

d

4

answer is A.

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Detailed Solution

cos3θ-cos3θcosθ+sin3θ+sin3θsinθ

cos3θ-3cos3θ+3cosθcosθ+sin3θ+3sinθ-4sin3θsinθ

3cosθ-3cos3θcosθ+3sinθ-3sin3θsinθ

=3-3cos2θ+3-3sin2θ

=6-3(cos2θ+sin2θ)

=6-3(1)

=3

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