cos5π4-sin5π4+tan11π4-cot11π4 =

cos5π4-sin5π4+tan11π4-cot11π4 cos5π4-sin5π4+tan11π4-cot11π4 =cosπ+π4-sinπ+π4+tan3π-π4-cot3π-π4=-cosπ4+sinπ4-tanπ4+cotπ4=-12+12-1+1=0

cos5π4-sin5π4+tan11π4-cot11π4 =

cos5π4-sin5π4+tan11π4-cot11π4 cos5π4-sin5π4+tan11π4-cot11π4 =cosπ+π4-sinπ+π4+tan3π-π4-cot3π-π4=-cosπ4+sinπ4-tanπ4+cotπ4=-12+12-1+1=0

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

$\cos \frac{5 π}{4} - \sin \frac{5 π}{4} + \tan \frac{11 π}{4} - c o t \frac{11 π}{4} =$

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

-1

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\cos \frac{5 π}{4} - \sin \frac{5 π}{4} + \tan \frac{11 π}{4} - \cot \frac{11 π}{4}$

$\begin{array}{l} \cos \frac{5 π}{4} - \sin \frac{5 π}{4} + \tan \frac{11 π}{4} - \cot \frac{11 π}{4} \\ = \cos (π + \frac{π}{4}) - \sin (π + \frac{π}{4}) + \tan (3 π - \frac{π}{4}) - \cot (3 π - \frac{π}{4}) \\ = - \cos \frac{π}{4} + \sin \frac{π}{4} - \tan \frac{π}{4} + \cot \frac{π}{4} \\ = - \frac{1}{\sqrt{2}} + \frac{1}{\sqrt{2}} - 1 + 1 = 0 \end{array}$