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$\cos [\sin^{- 1} (2 \cos^{2} θ - 1) + \cos^{- 1} (1 - 2 \sin^{2} θ)] =$

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$\frac{π}{2}$

-1

answer is A.

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Detailed Solution

$= \cos [\sin^{- 1} (2 \cos^{2} θ - 1) + \cos^{- 1} (1 - 2 \sin^{2} θ)]$

$= \cos (\sin^{- 1} (\cos 2 θ) + \cos^{- 1} (\sin 2 θ)) = \cos \frac{π}{2} = 0$

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