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Q.

cosx+xsinxx(x+cosx)dx=

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a

log|x(x+cosx)|+c

b

log|x(cosx+xsinx)|+c

c

logxx+cosx+c

d

logx+cosxx+c

answer is C.

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Detailed Solution

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cosx+xsinxx(x+cosx)dx

=(x+cosx)x(1sinx)x(x+cosx)dx

=1x1sinxx+cosxdx

=log|x|log|x+cosx|+c

=logxx+cosx+c

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