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Q.

cot2x.log(sinx)1log(sinx)3dx=

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a

23log(sinx)32+c

b

23sin1log(sinx)32+c

c

cotx+c

d

log(sinx)+c

answer is B.

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Detailed Solution

cot2x.log(sinx)1(log(sinx))3dx

=cotxlog(sinx)1[log(sinx)]322dx Let (log(sinx))32=t32cotxlog(sinx)dx=dt=2311t2dt=23sin1(t)+c

=23sin1(log(sinx))32+c

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