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Q.

$\cot A - \tan A - 2 \tan 2 A - 4 \tan 4 A =$

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a

$2 \cot 2 A$

b

$4 \cot 4 A$

c

$\cot A$

d

$8 \cot 8 A$

answer is D.

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Detailed Solution

$\cot A - \tan A - 2 \tan 2 A - 4 \tan 4 A$

$= 2 \cot 2 A - 2 \tan 2 A - 4 \tan 4 A$

$= 4 \cot 4 A - 4 \tan 4 A$

$= 8 \cot 8 A$

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cotA−tanA−2tan2A−4tan4A=