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C_p, C_v and vapour density of an elementary gas respectively are 0.125, 0.089 and 16. The atomic weight of element is

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answer is C.

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Detailed Solution

C_p = 0.125
C_V = 0.089

\large \frac{{{C_p}}}{{{C_v}}}\; = \;\gamma \; = \;1.4

, $γ$ indicates it is diatomic
VD of element = 16
MW of element = 2 x 16 = 32

Atomicity = 2

\large AW of element=\frac{32}{2}\;=\;16

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