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$C r C l_{3} .6 H_{2} O$ dissolve in water to form a complex species. If a solution prepared by dissolving 0.1 mole of $C r C l_{3} .6 H_{2} O$ in water is treated with excess silver nitrate solution, 0.2 mole of silver chloride is precipitated. Select CORRECT option for complex. (At.Wt. $C r = 52, O = 16, C l = 35.5, H = 1$ )

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It will exist in 2 geometrical isomeric form

When solution of 0.1 mole complex passed in cationic exchanger resulting solution required 0.2 mole $K O H$ for neutralization

Diamagnetic complex in which central metal is in $d^{2} s p^{3}$

It loses almost $6.75 %$ of its original mass on treatment with conc. $H_{2} S O_{4}$

answer is B, D.

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Detailed Solution

$C r C l_{3} .6 H_{2} O \to [C r {(H_{2} O)}_{5} C l] C l_{2} . H_{2} O$

$C r \Rightarrow [A r] 3 d^{5} 4 s^{1}$

Hybridisation $= d^{2} s p^{3}$

Magnetic nature – paramagnrtic

Molecular weight of $C r C l_{3} .6 H_{2} O = 266.5$

Treatment with conc. $H_{2} S O_{4},$ 1 mole of complex,loses one mole of $H_{2} O$

$∴$ Percentage loss in weight $= \frac{18}{266.5} \times 100 = 6.75 %$

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