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Q.

Critical angle for a certain wavelength of light in glass is 40°. Calculate the polarising angle and angle of refraction in glass corresponding to this. $(\sin 40^{0} = \frac{2}{3})$

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a

$47.3 °, 22.7 °$

b

$22.7 °, 47.3 °$

c

$57.3 °, 32.7 °$

d

$32.7 °, 57.3 °$

answer is A.

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Detailed Solution

We have, $μ = \frac{1}{\sin C} = \frac{1}{\sin 40^{0}} = 1.5$

If $i_{p}$ be the polarizing angle, then

$μ = \tan i_{p} \Rightarrow \tan i_{p} = 1.5$

$∴ i_{p} = \tan^{- 1} (1.5) = {57.3}^{0}$ (nearly)

Angle of refraction, $r = 90^{0} - i_{p}$

$= 90^{0} - {57.3}^{0} = {32.7}^{0}$

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Critical angle for a certain wavelength of light in glass is 40°. Calculate the polarising angle and angle of refraction in glass corresponding to this. sin400=23