Critical angles of 3 transparent media are 300 , 450 and 600 . If IP1,IP2 and IP3 are polarising angles, then.

μ=Tanip=1Sin⁡CSin⁡C1 Tan⁡ip2>Tan⁡ip3

Critical angles of 3 transparent media are 300 , 450 and 600 . If IP1,IP2 and IP3 are polarising angles, then.

μ=Tanip=1Sin⁡CSin⁡C1 Tan⁡ip2>Tan⁡ip3

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Critical angles of 3 transparent media are 30⁰ , 45⁰ and 60⁰ . If ${(I_{P})}_{1}, {(I_{P})}_{2} and {(I_{P})}_{3}$ are polarising angles, then.

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${(I_{P})}_{1} = {(I_{P})}_{2} = {(I_{P})}_{3}$

${(I_{P})}_{1} > {(I_{P})}_{2} > {(I_{P})}_{3}$

${(I_{P})}_{3} > {(I_{P})}_{2} > {(I_{P})}_{1}$

${(I_{P})}_{2} > {(I_{P})}_{1} > {(I_{P})}_{3}$

answer is B.

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$μ = {Tani}_{p} = \frac{1}{Sin C}$

$Sin C_{1} < Sin C_{2} < Sin C_{3}$

$∴ Tan {(i_{p})}_{1} > Tan {(i_{p})}_{2} > Tan {(i_{p})}_{3}$

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Critical angles of 3 transparent media are 300 , 450 and 600 . If IP1,IP2 and IP3 are polarising angles, then.

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Critical angles of 3 transparent media are 30⁰ , 45⁰ and 60⁰ . If ${(I_{P})}_{1}, {(I_{P})}_{2} and {(I_{P})}_{3}$ are polarising angles, then.