Critical constants for a real gas are given asTC=180KVC=0.1231L/molePC=45atmThe correct statement for the real gas is :

The actual volume of single gas molecule is 0.123 × 10 − 3 6.023 × 10 23 c c

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Critical constants for a real gas are given as
$\begin{aligned} T_{C} = 180 K \\ V_{C} = 0.1231 L / mole \\ P_{C} = 45 atm \end{aligned}$
The correct statement for the real gas is :

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The actual volume of single gas molecule is $(\frac{0.123 \times 10^{- 3}}{6.023 \times 10^{23}}) c c$

$b = 3 \times 0.123 L {mol}^{- 1}$

The Boyle's temperature is less than 1.80 K

Gas cannot be liquefied at 200 K

answer is D.

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(a) $V_{C} = 3 b$ volume of 1 molecule $= \frac{4}{3} π r^{3}$

(b) $b = \frac{0.1231}{3} = \frac{V_{C}}{12 N_{A}}$

(d) $At T > T_{C}$ gas can't be liquefied.

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